Dilution ratio

aztec1987

aztec1987

New member
Joined
Mar 29, 2013
Messages
668
Reaction score
0
I am trying to make 50oz of carpet shampoo in which calls for dilution ratio of 20:1 how much product do I need to add to my 50oz container? Thanks in advance.
 
I come up with 2.4oz of your carpet shampoo and 47.6oz of water for your container.
 
I could very easily put this in an algebra equation, but why? Put 2 1/2 ounces in the container and fill it. It's not rocket science.
 
ducksfan said:
I could very easily put this in an algebra equation, but why? Put 2 1/2 ounces in the container and fill it. It's not rocket science.
Click to expand...

It might be good for the group to see so you have the podium! :props:
 
Ha! Called out.

Ok. Let's see... x= ounces of water; y= ounces of solution

x+y =50; x/y = 20/1 or 20y=x or y=x/20

solve simultaneously

replace y in the first equation with what y equals in the second equation (x/20)

so: x + x/20 =50... multiply each term by 20 and... 20x + x = 1000 or
21x = 1000... divide each term by 21 and x = 47.619

going back to one of the original equations (x + y = 50), plug 47.619 in for x and solve for y (2.381).

2.381 ounces of solution mixed with 47.691 ounces of water

Now blast that sucker off to the moon!
 
ducksfan said:
Ha! Called out.

Ok. Let's see... x= ounces of water; y= ounces of solution

x+y =50; x/y = 20/1 or 20y=x or y=x/20

solve simultaneously

replace y in the first equation with what y equals in the second equation (x/20)

so: x + x/20 =50... multiply each term by 20 and... 20x + x = 1000 or
21x = 1000... divide each term by 21 and x = 47.619

going back to one of the original equations (x + y = 50), plug 47.619 in for x and solve for y (2.381).

2.381 ounces of solution mixed with 47.691 ounces of water

Now blast that sucker off to the moon!
Click to expand...

Can you convert that to density altitude? lol
 
BobbyG said:
It might be good for the group to see so you have the podium! :props:
Click to expand...

Actually, the best way to do this is the way mwoolfso did in post #3. (1) Add both sides of the ratio (20:1 = 21) (2) divide the total amount of final product desired by this number (for a gallon, 128/21 = 6.1) (3) then multiply this number by either part of the ratio to get the amount of ingredient to add (6.1 x 20 = 122oz and 6.1 x 1 = ~6oz).
 
ducksfan said:
Ha! Called out.

Ok. Let's see... x= ounces of water; y= ounces of solution

x+y =50; x/y = 20/1 or 20y=x or y=x/20

solve simultaneously

replace y in the first equation with what y equals in the second equation (x/20)

so: x + x/20 =50... multiply each term by 20 and... 20x + x = 1000 or
21x = 1000... divide each term by 21 and x = 47.619

going back to one of the original equations (x + y = 50), plug 47.619 in for x and solve for y (2.381).

2.381 ounces of solution mixed with 47.691 ounces of water

Now blast that sucker off to the moon!
Click to expand...

Now how cool is that for all you brainiacs! :props:

Thank you! :cheers:
 
You must log in or register to reply here.
Back
Top