The reason I said the ratio works perfect is that it makes things simple and gives an approximate cost.
Some answered 2 ounces used, some 4, and some 6. There's no way to know without going through the conversions which is a pain. So, we just simply use the real numbers given to us by the scale. It can be proved because those numbers don't lie...
The only way to find the real amount of fluid ounces used is to take the real world numbers that Mr. Phillips showed (2.6, 2.2, and .4 lbs.) and do a bunch of conversions. Cost per detail is the main concern and focus in Mr. Doyle's book, not the exact fluid ounce per detail. I don't have time for a bunch of converstions and looking at conversion charts.. In the restaurant business there's no time for it either. That's why I agreed with the fellow above. Ratio's make things simple and can be very accurate depending on how many numbers you use after the decimal. Just as in diluting products for detailing, the dilutions are given in ratios.
Just to show he was very close with his answer...
Here's what he said:
So... $48 divided by 2.6 x .4 = $7.3846 (152) ...OR...
$48/2.6 = 18.461538 x .4 = $7.3846 (152)
Now let's check his math. The real numbers given to us don't lie...as proved below.
2.6 divide by .4 = 6.5
6.5 x 7.3846 = $47.9999
I'd say he hit the dollar amount of product used by Mr. Phillips right on the horse...I mean head... LOL!...given that a quart of FG 400 costs $48.
It only gets complicated if you try and convert the numbers used (2.6, 2.2, and .4), numbers given as total mass pounds per the scale, to fluid ounces used.
Of course you could always go the long way around, and Bob is quite capable, however, I am not. The long way...
:dunno:
Good horse trainers speak softly and no longer beat their horses. :laughing:
Some answered 2 ounces used, some 4, and some 6. There's no way to know without going through the conversions which is a pain. So, we just simply use the real numbers given to us by the scale. It can be proved because those numbers don't lie...
The only way to find the real amount of fluid ounces used is to take the real world numbers that Mr. Phillips showed (2.6, 2.2, and .4 lbs.) and do a bunch of conversions. Cost per detail is the main concern and focus in Mr. Doyle's book, not the exact fluid ounce per detail. I don't have time for a bunch of converstions and looking at conversion charts.. In the restaurant business there's no time for it either. That's why I agreed with the fellow above. Ratio's make things simple and can be very accurate depending on how many numbers you use after the decimal. Just as in diluting products for detailing, the dilutions are given in ratios.
Just to show he was very close with his answer...
Here's what he said:
$48(cost for the bottle) to 2.6 Lbs is X(in dollars) to .4(difference between full bottle and the used bottle) or
$48 / 2.6 lbs = X / .4 lbs or ($48 / 2.6 lbs)(.4 lbs)= X
The weight of the empty bottle is irrelevant because it cancelled out.
So.... the cost for buffing out the car is X = $7.38 (give or take $.10).
So... $48 divided by 2.6 x .4 = $7.3846 (152) ...OR...
$48/2.6 = 18.461538 x .4 = $7.3846 (152)
Now let's check his math. The real numbers given to us don't lie...as proved below.
2.6 divide by .4 = 6.5
6.5 x 7.3846 = $47.9999
I'd say he hit the dollar amount of product used by Mr. Phillips right on the horse...I mean head... LOL!...given that a quart of FG 400 costs $48.
It only gets complicated if you try and convert the numbers used (2.6, 2.2, and .4), numbers given as total mass pounds per the scale, to fluid ounces used.
Of course you could always go the long way around, and Bob is quite capable, however, I am not. The long way...
Now to conversion of a liquid volume>liquid weight
-For example purposes: Water (other liquids to follow).
First:
-Based on 1 US liquid gallon/water = 231 in3; 1 inch = 2.54 cm.
Second:
-US system of weight/mass = Avoirdupois (Avdp.)...
Where 1lb = 16oz
-Third (Known scientific fact):
Water at room temp. (77F/25C), and 1 atmosphere (air pressure at sea level)
has a density of 997.13 kg/m3.
-A few multipliers/conversion factors:
1 m = 100 cm
1 kg = 1000 g
1 L = 1.0567 US quarts (qt)
1 lb = 16 oz = 453.59 g
997.13 kg/m3 (x) 1000 g/kg (x) 1 m/100 cm3 (x) 1000 cm3/L = 997.13 g/L
-Converting to US Avdp. Units:
(997.13 g/L) × (1 lb/453.59 g) × (1 L/1.0567 qt) = 2.0803 lb/qt
1 quart (US Volume) = .0.9464 L (Metric Volume) = 2.080 lb/33.29 oz (Avdp. Wgt.)
1 fluid ounce (US Volume) = 29.57 mL (Metric Volume) = 1.040 oz (Avdp. Wgt.)
Using Mike's Menzerna "weigh-ins"...With Water as the "product":
-Full FG400: 2.6lbs = 41.6 oz...including Water-product and bottle/lid assembly
-32 oz of Water actually weighs = 33.2848 oz
-Using this method:
41.60 oz (-) 33.28oz = 8.32 oz; which = Too much, IMO...
For the ~ Weight/Tare of an empty 32oz Menzerna FG400 bottle/lid assembly...
That is: if the product in the Bottle is Water
-And, as it has been mentioned:
Bottle/lid assembly---Relevant/Not Revelant? Material/Immaterial?
Known scientific fact:
-Specific gravity (sg) of water = 1.0000 at 39.2° F/4° C
-The thermal coefficient of the expansion of water is:
0.00021 per 1° Celsius at 20° Celsius.
Without its MSDS in front of me at the moment...
-What then could be the ingredients/chemicals in Menzerna FG400...
That are different than Water...
That would alter/boost the Weight of this compounding-product solution/emulsion,
that's within its said Bottle?
-Is Water one of the ingredients?
I assume it has solvents.
Here's a couple:
-Naphtha's sg = .66477..."Lighter" than Water
-Kerosene's sg =.81715...same as above
I assume it has abrasives:
Here's a few:
-Alumina's sg = .961...Weighs ~ same as Water
Aluminum oxide' sg = 1.522..."Heavier" than Water
Kaolin's sg = 1.025..."Heavier" than Water
I assume it has many other: "compound" ingredients/chemicals.
-Once a person had the specific gravities of all FG400-ingredients/chemicals;
and, if the Chemists' FG400 formulation was never strayed from when blending;
then, the mathematical equations could be readily solved by plugging in those numbers;
with, finally, the weight/tare of FG400's bottle could be obtained as well...IMHO.
Yet...
-Will a 32oz bottle of FG400 allow a person to compound between: 4-5.3 vehicles...
Even if this task was performed per/M.P.'s skill-level?
But...
Then there's that ol': 'Thermal coefficient of the expansion of'...rearing it's mugly head...
Dang My Luck!!
Bob
:dunno:
Good horse trainers speak softly and no longer beat their horses. :laughing:
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